What are the solutions to the equation 49b^2+35b=-6 ?

The solutions to the equation 49b^2+35b=-6 are b=-2/7 ,b=-3/7

Find the zeros of 49b^2+35b=-6

The zeros of 49b^2+35b=-6 are b=-2/7 ,b=-3/7

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49 b^{2} + 35 b = - 6

b = - \frac{2}{7}, b = - \frac{3}{7}

Decimal Notation

b = - 0.28571 \dots, b = - 0.42857 \dots

Solution steps

49 b^{2} + 35 b = - 6

Move

6

to the left side

49 b^{2} + 35 b + 6 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 \cdot 49 \cdot 6}{2 \cdot 49}

3 5^{2} - 4 \cdot 49 \cdot 6 = 7

b_{1, 2} = \frac{- 35 \pm 7}{2 \cdot 49}

Separate the solutions

b_{1} = \frac{- 35 + 7}{2 \cdot 49}, b_{2} = \frac{- 35 - 7}{2 \cdot 49}

b = \frac{- 35 + 7}{2 \cdot 49} : - \frac{2}{7}

b = \frac{- 35 - 7}{2 \cdot 49} : - \frac{3}{7}

The solutions to the quadratic equation are:

b = - \frac{2}{7}, b = - \frac{3}{7}

9 b^{2} - 25 = 0

2 x^{2} + \frac{7}{3} = 2 + \frac{5}{9}

4 - 3 x = - x^{2} + 3 x

8 x^{2} - 26 x + 15 = 0

2 x^{2} - 6 x + 1

What are the solutions to the equation 49b^2+35b=-6 ?
The solutions to the equation 49b^2+35b=-6 are b=-2/7 ,b=-3/7
Find the zeros of 49b^2+35b=-6
The zeros of 49b^2+35b=-6 are b=-2/7 ,b=-3/7