What are the solutions to the equation x^2+16x+47=0 ?

The solutions to the equation x^2+16x+47=0 are x=-8+sqrt(17),x=-8-sqrt(17)

Find the zeros of x^2+16x+47=0

The zeros of x^2+16x+47=0 are x=-8+sqrt(17),x=-8-sqrt(17)

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x^{2} + 16 x + 47 = 0

x = - 8 + 17, x = - 8 - 17

Decimal Notation

x = - 3.87689 \dots, x = - 12.12310 \dots

Solution steps

x^{2} + 16 x + 47 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 47}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 47 = 217

x_{1, 2} = \frac{- 16 \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 17}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 17}{2 \cdot 1}

x = \frac{- 16 + 2 17}{2 \cdot 1} : - 8 + 17

x = \frac{- 16 - 2 17}{2 \cdot 1} : - 8 - 17

The solutions to the quadratic equation are:

x = - 8 + 17, x = - 8 - 17

b^{2} - 8 b + 15 = 0

t^{2} - 2 t + 1 = 36

x, x^{2} + y^{2} + 6 x - 4 y + 13 = 0

3 t^{2} - t - 6

4 x^{2} + 1.32 x - 0.33 = 0

What are the solutions to the equation x^2+16x+47=0 ?
The solutions to the equation x^2+16x+47=0 are x=-8+sqrt(17),x=-8-sqrt(17)
Find the zeros of x^2+16x+47=0
The zeros of x^2+16x+47=0 are x=-8+sqrt(17),x=-8-sqrt(17)