What are the solutions to the equation -3n^2+4n-59=-4n^2 ?

The solutions to the equation -3n^2+4n-59=-4n^2 are n=-2+3sqrt(7),n=-2-3sqrt(7)

Find the zeros of -3n^2+4n-59=-4n^2

The zeros of -3n^2+4n-59=-4n^2 are n=-2+3sqrt(7),n=-2-3sqrt(7)

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- 3 n^{2} + 4 n - 59 = - 4 n^{2}

n = - 2 + 37, n = - 2 - 37

Decimal Notation

n = 5.93725 \dots, n = - 9.93725 \dots

Solution steps

- 3 n^{2} + 4 n - 59 = - 4 n^{2}

Move

4 n^{2}

to the left side

n^{2} + 4 n - 59 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 59 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 59) = 67

n_{1, 2} = \frac{- 4 \pm 6 7}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 4 + 6 7}{2 \cdot 1}, n_{2} = \frac{- 4 - 6 7}{2 \cdot 1}

n = \frac{- 4 + 6 7}{2 \cdot 1} : - 2 + 37

n = \frac{- 4 - 6 7}{2 \cdot 1} : - 2 - 37

The solutions to the quadratic equation are:

n = - 2 + 37, n = - 2 - 37

(3 x) ln (2) = ln (34)

\frac{1}{x - 2} < \frac{2}{3 x - 9}

x^{2} - x = 3 x

4 c^{2} - 1

∣ 2 a + 7 ∣ + 7 = 4

What are the solutions to the equation -3n^2+4n-59=-4n^2 ?
The solutions to the equation -3n^2+4n-59=-4n^2 are n=-2+3sqrt(7),n=-2-3sqrt(7)
Find the zeros of -3n^2+4n-59=-4n^2
The zeros of -3n^2+4n-59=-4n^2 are n=-2+3sqrt(7),n=-2-3sqrt(7)