What are the solutions to the equation (x^2-36)/8+(x^2-64)/6 =14 ?

The solutions to the equation (x^2-36)/8+(x^2-64)/6 =14 are x=10,x=-10

Find the zeros of (x^2-36)/8+(x^2-64)/6 =14

The zeros of (x^2-36)/8+(x^2-64)/6 =14 are x=10,x=-10

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\frac{x ^{2} - 36}{8} + \frac{x ^{2} - 64}{6} = 14

x = 10, x = - 10

Solution steps

\frac{x ^{2} - 36}{8} + \frac{x ^{2} - 64}{6} = 14

Multiply by LCM

3 (x^{2} - 36) + 4 (x^{2} - 64) = 336

Expand

3 (x^{2} - 36) + 4 (x^{2} - 64) : 7 x^{2} - 364

7 x^{2} - 364 = 336

Move

364

to the right side

7 x^{2} = 700

Divide both sides by

7

x^{2} = 100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 100, x = - 100

100 = 10

- 100 = - 10

x = 10, x = - 10

x (x + 3) = 5 x

\frac{2}{15} x^{2} + (- \frac{1}{6} + \frac{1}{10}) x = \frac{1}{8}

λ^{2} + 4 λ - 5 (1) = 0

x^{2} - 16 x + 16 = 2 x - 20

2 x (x - 14) + 11 (3 + x) = - 22 x + 27 + x^{2}

What are the solutions to the equation (x^2-36)/8+(x^2-64)/6 =14 ?
The solutions to the equation (x^2-36)/8+(x^2-64)/6 =14 are x=10,x=-10
Find the zeros of (x^2-36)/8+(x^2-64)/6 =14
The zeros of (x^2-36)/8+(x^2-64)/6 =14 are x=10,x=-10