What are the solutions to the equation x^2-16x+16=2x-20 ?

The solutions to the equation x^2-16x+16=2x-20 are x=3(3+sqrt(5)),x=3(3-sqrt(5))

Find the zeros of x^2-16x+16=2x-20

The zeros of x^2-16x+16=2x-20 are x=3(3+sqrt(5)),x=3(3-sqrt(5))

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x^{2} - 16 x + 16 = 2 x - 20

x = 3 (3 + 5), x = 3 (3 - 5)

Decimal Notation

x = 15.70820 \dots, x = 2.29179 \dots

Solution steps

x^{2} - 16 x + 16 = 2 x - 20

Move

20

to the left side

x^{2} - 16 x + 36 = 2 x

Move

2 x

to the left side

x^{2} - 18 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 36 = 65

x_{1, 2} = \frac{- ( - 18 ) \pm 6 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 5}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 6 5}{2 \cdot 1}

x = \frac{- ( - 18 ) + 6 5}{2 \cdot 1} : 3 (3 + 5)

x = \frac{- ( - 18 ) - 6 5}{2 \cdot 1} : 3 (3 - 5)

The solutions to the quadratic equation are:

x = 3 (3 + 5), x = 3 (3 - 5)

2 x (x - 14) + 11 (3 + x) = - 22 x + 27 + x^{2}

- 2 x^{2} - 4 x + 30 = 0

t, y = v t + \frac{1}{2} g t^{2}

4 m^{2} + 200 m - 68696.06 = 0

2 a^{2} - 2 a - 3 = 0

What are the solutions to the equation x^2-16x+16=2x-20 ?
The solutions to the equation x^2-16x+16=2x-20 are x=3(3+sqrt(5)),x=3(3-sqrt(5))
Find the zeros of x^2-16x+16=2x-20
The zeros of x^2-16x+16=2x-20 are x=3(3+sqrt(5)),x=3(3-sqrt(5))