What are the solutions to the equation -2x^2-4x+30=0 ?

The solutions to the equation -2x^2-4x+30=0 are x=-5,x=3

Find the zeros of -2x^2-4x+30=0

The zeros of -2x^2-4x+30=0 are x=-5,x=3

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- 2 x^{2} - 4 x + 30 = 0

x = - 5, x = 3

Solution steps

- 2 x^{2} - 4 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) \cdot 30}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) \cdot 30 = 16

x_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 16}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 16}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 16}{2 ( - 2 )} : - 5

x = \frac{- ( - 4 ) - 16}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = - 5, x = 3

t, y = v t + \frac{1}{2} g t^{2}

4 m^{2} + 200 m - 68696.06 = 0

2 a^{2} - 2 a - 3 = 0

2 x^{2} - x + 4

(2 x + 3)^{2} = 5

What are the solutions to the equation -2x^2-4x+30=0 ?
The solutions to the equation -2x^2-4x+30=0 are x=-5,x=3
Find the zeros of -2x^2-4x+30=0
The zeros of -2x^2-4x+30=0 are x=-5,x=3