What are the solutions to the equation 4x^2+12x+32=0 ?

The solutions to the equation 4x^2+12x+32=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2

Find the zeros of 4x^2+12x+32=0

The zeros of 4x^2+12x+32=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2

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4 x^{2} + 12 x + 32 = 0

x = - \frac{3}{2} + i \frac{23}{2}, x = - \frac{3}{2} - i \frac{23}{2}

Solution steps

4 x^{2} + 12 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 32}{2 \cdot 4}

Simplify

1 2^{2} - 4 \cdot 4 \cdot 32 : 423 i

x_{1, 2} = \frac{- 12 \pm 4 23 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 4 23 i}{2 \cdot 4}, x_{2} = \frac{- 12 - 4 23 i}{2 \cdot 4}

x = \frac{- 12 + 4 23 i}{2 \cdot 4} : - \frac{3}{2} + i \frac{23}{2}

x = \frac{- 12 - 4 23 i}{2 \cdot 4} : - \frac{3}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{23}{2}, x = - \frac{3}{2} - i \frac{23}{2}

(x - 2)^{2} + (\frac{4}{3} x + \frac{4}{3} - 4)^{2} = 16

(x + 3) (x + 5) = 48

4 p^{2} - 4 = 0

x^{2} + 4 x + x = 0

9 v^{2} + 30 v = - 25

What are the solutions to the equation 4x^2+12x+32=0 ?
The solutions to the equation 4x^2+12x+32=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2
Find the zeros of 4x^2+12x+32=0
The zeros of 4x^2+12x+32=0 are x=-3/2+i(sqrt(23))/2 ,x=-3/2-i(sqrt(23))/2