What are the solutions to the equation 4p^2-4=0 ?

The solutions to the equation 4p^2-4=0 are p=1,p=-1

Find the zeros of 4p^2-4=0

The zeros of 4p^2-4=0 are p=1,p=-1

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4 p^{2} - 4 = 0

p = 1, p = - 1

Solution steps

4 p^{2} - 4 = 0

Move

4

to the right side

4 p^{2} = 4

Divide both sides by

4

p^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = 1, p = - 1

1 = 1

- 1 = - 1

p = 1, p = - 1

x^{2} + 4 x + x = 0

9 v^{2} + 30 v = - 25

7 f^{2} = f + 1

A (x) = x^{2}

x^{2} + (x - 2)^{2} = 130

What are the solutions to the equation 4p^2-4=0 ?
The solutions to the equation 4p^2-4=0 are p=1,p=-1
Find the zeros of 4p^2-4=0
The zeros of 4p^2-4=0 are p=1,p=-1