What are the solutions to the equation x^2+(x-2)^2=130 ?

The solutions to the equation x^2+(x-2)^2=130 are x=9,x=-7

Find the zeros of x^2+(x-2)^2=130

The zeros of x^2+(x-2)^2=130 are x=9,x=-7

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x^{2} + (x - 2)^{2} = 130

x = 9, x = - 7

Solution steps

x^{2} + (x - 2)^{2} = 130

Expand

x^{2} + (x - 2)^{2} : 2 x^{2} - 4 x + 4

2 x^{2} - 4 x + 4 = 130

Move

130

to the left side

2 x^{2} - 4 x - 126 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 2 ( - 126 )}{2 \cdot 2}

(- 4)^{2} - 4 \cdot 2 (- 126) = 32

x_{1, 2} = \frac{- ( - 4 ) \pm 32}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 32}{2 \cdot 2}, x_{2} = \frac{- ( - 4 ) - 32}{2 \cdot 2}

x = \frac{- ( - 4 ) + 32}{2 \cdot 2} : 9

x = \frac{- ( - 4 ) - 32}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = 9, x = - 7

x, x^{2} + (y - a)^{2} = \frac{1}{b}

m^{2} - 2 m + 10 = 0

x, (x - 6)^{2} + (y + 4)^{2} + z^{2} = 25

x^{2} = 7 x - 6

- x^{2} - 10 x = 34

What are the solutions to the equation x^2+(x-2)^2=130 ?
The solutions to the equation x^2+(x-2)^2=130 are x=9,x=-7
Find the zeros of x^2+(x-2)^2=130
The zeros of x^2+(x-2)^2=130 are x=9,x=-7