What are the solutions to the equation -4x^2-8x+5=0 ?

The solutions to the equation -4x^2-8x+5=0 are x=-5/2 ,x= 1/2

Find the zeros of -4x^2-8x+5=0

The zeros of -4x^2-8x+5=0 are x=-5/2 ,x= 1/2

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- 4 x^{2} - 8 x + 5 = 0

x = - \frac{5}{2}, x = \frac{1}{2}

Decimal Notation

x = - 2.5, x = 0.5

Solution steps

- 4 x^{2} - 8 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 4 ) \cdot 5}{2 ( - 4 )}

(- 8)^{2} - 4 (- 4) \cdot 5 = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 ( - 4 )}, x_{2} = \frac{- ( - 8 ) - 12}{2 ( - 4 )}

x = \frac{- ( - 8 ) + 12}{2 ( - 4 )} : - \frac{5}{2}

x = \frac{- ( - 8 ) - 12}{2 ( - 4 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = \frac{1}{2}

x^{2} + 4 = - 2 x + 3

- x^{2} + 4 x + 3 = x - 1

x^{2} = x + 4

3^{2} = x^{2} + 2^{2}

(x - \frac{\frac{7}{6}}{2})^{2} - (\frac{\frac{- 7}{6}}{2})^{2} - \frac{1}{4} = 0

What are the solutions to the equation -4x^2-8x+5=0 ?
The solutions to the equation -4x^2-8x+5=0 are x=-5/2 ,x= 1/2
Find the zeros of -4x^2-8x+5=0
The zeros of -4x^2-8x+5=0 are x=-5/2 ,x= 1/2