What are the solutions to the equation a^2+16^2=18^2 ?

The solutions to the equation a^2+16^2=18^2 are a=2sqrt(17),a=-2sqrt(17)

Find the zeros of a^2+16^2=18^2

The zeros of a^2+16^2=18^2 are a=2sqrt(17),a=-2sqrt(17)

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a^{2} + 1 6^{2} = 1 8^{2}

a = 217, a = - 217

Decimal Notation

a = 8.24621 \dots, a = - 8.24621 \dots

Solution steps

a^{2} + 1 6^{2} = 1 8^{2}

Move

1 6^{2}

to the right side

a^{2} = 68

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 68, a = - 68

68 = 217

- 68 = - 217

a = 217, a = - 217

n^{2} + 3 n - 28 = 0

3 + 5 x - 2 x^{2} = 0

6 x^{2} + 9 x + 2 = - 2 - 4 x - 3 x^{2}

6 p - 6 = p^{2}

2 x^{2} - 9 x - 2 = - 6

What are the solutions to the equation a^2+16^2=18^2 ?
The solutions to the equation a^2+16^2=18^2 are a=2sqrt(17),a=-2sqrt(17)
Find the zeros of a^2+16^2=18^2
The zeros of a^2+16^2=18^2 are a=2sqrt(17),a=-2sqrt(17)