What are the solutions to the equation 5y^2-25y=0 ?

The solutions to the equation 5y^2-25y=0 are y=5,y=0

Find the zeros of 5y^2-25y=0

The zeros of 5y^2-25y=0 are y=5,y=0

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5 y^{2} - 25 y = 0

y = 5, y = 0

Solution steps

5 y^{2} - 25 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 25)^{2} - 4 \cdot 5 \cdot 0 = 25

y_{1, 2} = \frac{- ( - 25 ) \pm 25}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- ( - 25 ) + 25}{2 \cdot 5}, y_{2} = \frac{- ( - 25 ) - 25}{2 \cdot 5}

y = \frac{- ( - 25 ) + 25}{2 \cdot 5} : 5

y = \frac{- ( - 25 ) - 25}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

y = 5, y = 0

0.1 x^{2} - 30 x + 1760 = 0

1 8^{2} = 9^{2} + x^{2}

\frac{1}{2} x^{2} = 50

(2 x - 3)^{2} = 8 x

7 y - 10 = y^{2}

What are the solutions to the equation 5y^2-25y=0 ?
The solutions to the equation 5y^2-25y=0 are y=5,y=0
Find the zeros of 5y^2-25y=0
The zeros of 5y^2-25y=0 are y=5,y=0