What are the solutions to the equation 7y-10=y^2 ?

The solutions to the equation 7y-10=y^2 are y=5,y=2

Find the zeros of 7y-10=y^2

The zeros of 7y-10=y^2 are y=5,y=2

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7 y - 10 = y^{2}

y = 5, y = 2

Solution steps

7 y - 10 = y^{2}

Switch sides

y^{2} = 7 y - 10

Move

10

to the left side

y^{2} + 10 = 7 y

Move

7 y

to the left side

y^{2} + 10 - 7 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 7 y + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

y_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, y_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

y = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

y = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

y = 5, y = 2

12 x^{2} - 280 x + 1200 = 0

3 x^{2} + 17 = - 10 x + 9

2 z^{2} - 1 = 0

a^{2} = 5 a

5 x^{2} - 3 x + 1 = 10

What are the solutions to the equation 7y-10=y^2 ?
The solutions to the equation 7y-10=y^2 are y=5,y=2
Find the zeros of 7y-10=y^2
The zeros of 7y-10=y^2 are y=5,y=2