What are the solutions to the equation 2z^2-1=0 ?

The solutions to the equation 2z^2-1=0 are z= 1/(sqrt(2)),z=-1/(sqrt(2))

Find the zeros of 2z^2-1=0

The zeros of 2z^2-1=0 are z= 1/(sqrt(2)),z=-1/(sqrt(2))

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2 z^{2} - 1 = 0

z = \frac{1}{2}, z = - \frac{1}{2}

Decimal Notation

z = 0.70710 \dots, z = - 0.70710 \dots

Solution steps

2 z^{2} - 1 = 0

Move

1

to the right side

2 z^{2} = 1

Divide both sides by

2

z^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = \frac{1}{2}, z = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

z = \frac{1}{2}, z = - \frac{1}{2}

a^{2} = 5 a

5 x^{2} - 3 x + 1 = 10

7 x^{2} = - 9 x - 3

m^{2} + 6 m = - 8

x^{2} + 10 x - 3

What are the solutions to the equation 2z^2-1=0 ?
The solutions to the equation 2z^2-1=0 are z= 1/(sqrt(2)),z=-1/(sqrt(2))
Find the zeros of 2z^2-1=0
The zeros of 2z^2-1=0 are z= 1/(sqrt(2)),z=-1/(sqrt(2))