What are the solutions to the equation -6=x^2+4x-1 ?

The solutions to the equation -6=x^2+4x-1 are x=-2+i,x=-2-i

Find the zeros of -6=x^2+4x-1

The zeros of -6=x^2+4x-1 are x=-2+i,x=-2-i

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- 6 = x^{2} + 4 x - 1

x = - 2 + i, x = - 2 - i

Solution steps

- 6 = x^{2} + 4 x - 1

Switch sides

x^{2} + 4 x - 1 = - 6

Move

6

to the left side

x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

x = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

x = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

x = - 2 + i, x = - 2 - i

x, y^{2} + 2 x y + 6 x^{2} = 8

4 + 6 x - 9 x^{2} = 0

(- 2 y - 1)^{2} + (y - 1)^{2} = 5

x^{2} - 16 x + 50 = 21

4 t^{2} - 19 t + 18 = 0

What are the solutions to the equation -6=x^2+4x-1 ?
The solutions to the equation -6=x^2+4x-1 are x=-2+i,x=-2-i
Find the zeros of -6=x^2+4x-1
The zeros of -6=x^2+4x-1 are x=-2+i,x=-2-i