What are the solutions to the equation x^2-x-6=-4 ?

The solutions to the equation x^2-x-6=-4 are x=2,x=-1

Find the zeros of x^2-x-6=-4

The zeros of x^2-x-6=-4 are x=2,x=-1

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x^{2} - x - 6 = - 4

x = 2, x = - 1

Solution steps

x^{2} - x - 6 = - 4

Move

4

to the left side

x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

x = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

0 = 5 x^{2} - 20 x + 4

3 k^{2} + k - 11 = - 4

6 x^{2} - 14 = 0

(x - 3) (x - 2) = (x + 5) (2 x - 3) + 21

x^{2} + 6 x + 2 = 0

What are the solutions to the equation x^2-x-6=-4 ?
The solutions to the equation x^2-x-6=-4 are x=2,x=-1
Find the zeros of x^2-x-6=-4
The zeros of x^2-x-6=-4 are x=2,x=-1