What are the solutions to the equation 0=5x^2-20x+4 ?

The solutions to the equation 0=5x^2-20x+4 are x=(2(5+2sqrt(5)))/5 ,x=(2(5-2sqrt(5)))/5

Find the zeros of 0=5x^2-20x+4

The zeros of 0=5x^2-20x+4 are x=(2(5+2sqrt(5)))/5 ,x=(2(5-2sqrt(5)))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 5 x^{2} - 20 x + 4

x = \frac{2 ( 5 + 2 5 )}{5}, x = \frac{2 ( 5 - 2 5 )}{5}

Decimal Notation

x = 3.78885 \dots, x = 0.21114 \dots

Solution steps

0 = 5 x^{2} - 20 x + 4

Switch sides

5 x^{2} - 20 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 4 = 85

x_{1, 2} = \frac{- ( - 20 ) \pm 8 5}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8 5}{2 \cdot 5}, x_{2} = \frac{- ( - 20 ) - 8 5}{2 \cdot 5}

x = \frac{- ( - 20 ) + 8 5}{2 \cdot 5} : \frac{2 ( 5 + 2 5 )}{5}

x = \frac{- ( - 20 ) - 8 5}{2 \cdot 5} : \frac{2 ( 5 - 2 5 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 5 + 2 5 )}{5}, x = \frac{2 ( 5 - 2 5 )}{5}

3 k^{2} + k - 11 = - 4

6 x^{2} - 14 = 0

(x - 3) (x - 2) = (x + 5) (2 x - 3) + 21

x^{2} + 6 x + 2 = 0

9 x^{2} + 17 x - 2 = 0

What are the solutions to the equation 0=5x^2-20x+4 ?
The solutions to the equation 0=5x^2-20x+4 are x=(2(5+2sqrt(5)))/5 ,x=(2(5-2sqrt(5)))/5
Find the zeros of 0=5x^2-20x+4
The zeros of 0=5x^2-20x+4 are x=(2(5+2sqrt(5)))/5 ,x=(2(5-2sqrt(5)))/5