What are the solutions to the equation x^2+8x=105 ?

The solutions to the equation x^2+8x=105 are x=7,x=-15

Find the zeros of x^2+8x=105

The zeros of x^2+8x=105 are x=7,x=-15

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x^{2} + 8 x = 105

x = 7, x = - 15

Solution steps

x^{2} + 8 x = 105

Move

105

to the left side

x^{2} + 8 x - 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 105 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 105) = 22

x_{1, 2} = \frac{- 8 \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 22}{2 \cdot 1}, x_{2} = \frac{- 8 - 22}{2 \cdot 1}

x = \frac{- 8 + 22}{2 \cdot 1} : 7

x = \frac{- 8 - 22}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 7, x = - 15

3 x^{2} - 29 x + 26 = 0

9 x^{2} - 12 x + 4 = - 3

x, z = x y (3 - x - y)

b^{2} + 3 b - 18 = 0

y, x^{3} + x^{2} y^{2} - 4 x - 2 y = 0

What are the solutions to the equation x^2+8x=105 ?
The solutions to the equation x^2+8x=105 are x=7,x=-15
Find the zeros of x^2+8x=105
The zeros of x^2+8x=105 are x=7,x=-15