What are the solutions to the equation -10x^2-4x+2=0 ?

The solutions to the equation -10x^2-4x+2=0 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5

Find the zeros of -10x^2-4x+2=0

The zeros of -10x^2-4x+2=0 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5

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- 10 x^{2} - 4 x + 2 = 0

x = - \frac{1 + 6}{5}, x = \frac{6 - 1}{5}

Decimal Notation

x = - 0.68989 \dots, x = 0.28989 \dots

Solution steps

- 10 x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 10 ) \cdot 2}{2 ( - 10 )}

(- 4)^{2} - 4 (- 10) \cdot 2 = 46

x_{1, 2} = \frac{- ( - 4 ) \pm 4 6}{2 ( - 10 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 6}{2 ( - 10 )}, x_{2} = \frac{- ( - 4 ) - 4 6}{2 ( - 10 )}

x = \frac{- ( - 4 ) + 4 6}{2 ( - 10 )} : - \frac{1 + 6}{5}

x = \frac{- ( - 4 ) - 4 6}{2 ( - 10 )} : \frac{6 - 1}{5}

The solutions to the quadratic equation are:

x = - \frac{1 + 6}{5}, x = \frac{6 - 1}{5}

1 + 0.2 x + 0.7 x^{2} = 0

\frac{1}{6} n^{2} - \frac{1}{2} n - \frac{2}{3} = 0

(x + 3)^{2} + 3 x^{2} = 10 x + 8

x^{2} + 70 x - 3000 = 0

y, x^{3} + x y^{2} = 2

What are the solutions to the equation -10x^2-4x+2=0 ?
The solutions to the equation -10x^2-4x+2=0 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5
Find the zeros of -10x^2-4x+2=0
The zeros of -10x^2-4x+2=0 are x=-(1+sqrt(6))/5 ,x=(sqrt(6)-1)/5