What are the solutions to the equation 3u^2-6u=0 ?

The solutions to the equation 3u^2-6u=0 are u=2,u=0

Find the zeros of 3u^2-6u=0

The zeros of 3u^2-6u=0 are u=2,u=0

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3 u^{2} - 6 u = 0

u = 2, u = 0

Solution steps

3 u^{2} - 6 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 0 = 6

u_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 3}

Separate the solutions

u_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 3}, u_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 3}

u = \frac{- ( - 6 ) + 6}{2 \cdot 3} : 2

u = \frac{- ( - 6 ) - 6}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

u = 2, u = 0

x, z = 27 - 2 x^{2} - 2 y^{2}

- \frac{224}{10} x = 7 (x + 4) (x - 8)

x + 1 = (x - 2)^{2} - 3

32 = x^{2} + 4 x

u^{2} - 3 u - 18 = 0

What are the solutions to the equation 3u^2-6u=0 ?
The solutions to the equation 3u^2-6u=0 are u=2,u=0
Find the zeros of 3u^2-6u=0
The zeros of 3u^2-6u=0 are u=2,u=0