What are the solutions to the equation u^2-3u-18=0 ?

The solutions to the equation u^2-3u-18=0 are u=6,u=-3

Find the zeros of u^2-3u-18=0

The zeros of u^2-3u-18=0 are u=6,u=-3

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u^{2} - 3 u - 18 = 0

u = 6, u = - 3

Solution steps

u^{2} - 3 u - 18 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 18) = 9

u_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 1}, u_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 1}

u = \frac{- ( - 3 ) + 9}{2 \cdot 1} : 6

u = \frac{- ( - 3 ) - 9}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

u = 6, u = - 3

3 x^{2} - 688 x + 25300 = 0

r = 4 r^{2} - 1

x^{2} + 2 x + 100 = 0

y^{2} + 11 y + 28 = 0

6 x^{2} - 23 x - 18 = 0

What are the solutions to the equation u^2-3u-18=0 ?
The solutions to the equation u^2-3u-18=0 are u=6,u=-3
Find the zeros of u^2-3u-18=0
The zeros of u^2-3u-18=0 are u=6,u=-3