What are the solutions to the equation x^2+2x+100=0 ?

The solutions to the equation x^2+2x+100=0 are x=-1+3sqrt(11)i,x=-1-3sqrt(11)i

Find the zeros of x^2+2x+100=0

The zeros of x^2+2x+100=0 are x=-1+3sqrt(11)i,x=-1-3sqrt(11)i

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x^{2} + 2 x + 100 = 0

x = - 1 + 311 i, x = - 1 - 311 i

Solution steps

x^{2} + 2 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 100 : 611 i

x_{1, 2} = \frac{- 2 \pm 6 11 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6 11 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 6 11 i}{2 \cdot 1}

x = \frac{- 2 + 6 11 i}{2 \cdot 1} : - 1 + 311 i

x = \frac{- 2 - 6 11 i}{2 \cdot 1} : - 1 - 311 i

The solutions to the quadratic equation are:

x = - 1 + 311 i, x = - 1 - 311 i

y^{2} + 11 y + 28 = 0

6 x^{2} - 23 x - 18 = 0

2 x^{2} + 5 x - 250 = 0

6 x^{2} + 2 x - 5 = 0

y^{2} - 32 y

What are the solutions to the equation x^2+2x+100=0 ?
The solutions to the equation x^2+2x+100=0 are x=-1+3sqrt(11)i,x=-1-3sqrt(11)i
Find the zeros of x^2+2x+100=0
The zeros of x^2+2x+100=0 are x=-1+3sqrt(11)i,x=-1-3sqrt(11)i