What are the solutions to the equation 2x^2+5x-250=0 ?

The solutions to the equation 2x^2+5x-250=0 are x=10,x=-25/2

Find the zeros of 2x^2+5x-250=0

The zeros of 2x^2+5x-250=0 are x=10,x=-25/2

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2 x^{2} + 5 x - 250 = 0

x = 10, x = - \frac{25}{2}

Decimal Notation

x = 10, x = - 12.5

Solution steps

2 x^{2} + 5 x - 250 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 250 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 250) = 45

x_{1, 2} = \frac{- 5 \pm 45}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 45}{2 \cdot 2}, x_{2} = \frac{- 5 - 45}{2 \cdot 2}

x = \frac{- 5 + 45}{2 \cdot 2} : 10

x = \frac{- 5 - 45}{2 \cdot 2} : - \frac{25}{2}

The solutions to the quadratic equation are:

x = 10, x = - \frac{25}{2}

6 x^{2} + 2 x - 5 = 0

y^{2} - 32 y

\frac{( x - 2 ) ^{2}}{3} + \frac{14 x - 5}{6} = \frac{11}{6}

- 0.2 x^{2} + 6 x + 10 = 0

3 x (x + 3) = 8

What are the solutions to the equation 2x^2+5x-250=0 ?
The solutions to the equation 2x^2+5x-250=0 are x=10,x=-25/2
Find the zeros of 2x^2+5x-250=0
The zeros of 2x^2+5x-250=0 are x=10,x=-25/2