What are the solutions to the equation -0.2x^2+6x+10=0 ?

The solutions to the equation -0.2x^2+6x+10=0 are x=-5(sqrt(11)-3),x=5(3+sqrt(11))

Find the zeros of -0.2x^2+6x+10=0

The zeros of -0.2x^2+6x+10=0 are x=-5(sqrt(11)-3),x=5(3+sqrt(11))

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- 0.2 x^{2} + 6 x + 10 = 0

x = - 5 (11 - 3), x = 5 (3 + 11)

Decimal Notation

x = - 1.58312 \dots, x = 31.58312 \dots

Solution steps

- 0.2 x^{2} + 6 x + 10 = 0

Multiply both sides by

10

- 2 x^{2} + 60 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 ( - 2 ) \cdot 100}{2 ( - 2 )}

6 0^{2} - 4 (- 2) \cdot 100 = 2011

x_{1, 2} = \frac{- 60 \pm 20 11}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 60 + 20 11}{2 ( - 2 )}, x_{2} = \frac{- 60 - 20 11}{2 ( - 2 )}

x = \frac{- 60 + 20 11}{2 ( - 2 )} : - 5 (11 - 3)

x = \frac{- 60 - 20 11}{2 ( - 2 )} : 5 (3 + 11)

The solutions to the quadratic equation are:

x = - 5 (11 - 3), x = 5 (3 + 11)

3 x (x + 3) = 8

8 x^{2} + 4 x = - 1

2 n^{2} + n - 2035 = 0

x, 4 x^{2} + y^{2} - 4 z^{2} - 4 = 0

x^{2} - 6 x - 27 = 0

What are the solutions to the equation -0.2x^2+6x+10=0 ?
The solutions to the equation -0.2x^2+6x+10=0 are x=-5(sqrt(11)-3),x=5(3+sqrt(11))
Find the zeros of -0.2x^2+6x+10=0
The zeros of -0.2x^2+6x+10=0 are x=-5(sqrt(11)-3),x=5(3+sqrt(11))