What are the solutions to the equation 8x^2+4x=-1 ?

The solutions to the equation 8x^2+4x=-1 are x=-1/4+i 1/4 ,x=-1/4-i 1/4

Find the zeros of 8x^2+4x=-1

The zeros of 8x^2+4x=-1 are x=-1/4+i 1/4 ,x=-1/4-i 1/4

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8 x^{2} + 4 x = - 1

x = - \frac{1}{4} + i \frac{1}{4}, x = - \frac{1}{4} - i \frac{1}{4}

Solution steps

8 x^{2} + 4 x = - 1

Move

1

to the left side

8 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

Simplify

4^{2} - 4 \cdot 8 \cdot 1 : 4 i

x_{1, 2} = \frac{- 4 \pm 4 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 4 + 4 i}{2 \cdot 8}, x_{2} = \frac{- 4 - 4 i}{2 \cdot 8}

x = \frac{- 4 + 4 i}{2 \cdot 8} : - \frac{1}{4} + i \frac{1}{4}

x = \frac{- 4 - 4 i}{2 \cdot 8} : - \frac{1}{4} - i \frac{1}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{1}{4}, x = - \frac{1}{4} - i \frac{1}{4}

2 n^{2} + n - 2035 = 0

x, 4 x^{2} + y^{2} - 4 z^{2} - 4 = 0

x^{2} - 6 x - 27 = 0

(2 x + 3)^{2} - 108 = 0

x, 2 (m x - 1)^{2} = m (2 x - 1)^{2}

What are the solutions to the equation 8x^2+4x=-1 ?
The solutions to the equation 8x^2+4x=-1 are x=-1/4+i 1/4 ,x=-1/4-i 1/4
Find the zeros of 8x^2+4x=-1
The zeros of 8x^2+4x=-1 are x=-1/4+i 1/4 ,x=-1/4-i 1/4