What are the solutions to the equation (2x+3)^2-108=0 ?

The solutions to the equation (2x+3)^2-108=0 are x=(6sqrt(3)-3)/2 ,x=(-6sqrt(3)-3)/2

Find the zeros of (2x+3)^2-108=0

The zeros of (2x+3)^2-108=0 are x=(6sqrt(3)-3)/2 ,x=(-6sqrt(3)-3)/2

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(2 x + 3)^{2} - 108 = 0

x = \frac{6 3 - 3}{2}, x = \frac{- 6 3 - 3}{2}

Decimal Notation

x = 3.69615 \dots, x = - 6.69615 \dots

Solution steps

(2 x + 3)^{2} - 108 = 0

Move

108

to the right side

(2 x + 3)^{2} = 108

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = 108 : x = \frac{6 3 - 3}{2}

Solve

2 x + 3 = - 108 : x = \frac{- 6 3 - 3}{2}

The solutions to the quadratic equation are:

x = \frac{6 3 - 3}{2}, x = \frac{- 6 3 - 3}{2}

x, 2 (m x - 1)^{2} = m (2 x - 1)^{2}

x^{2} + 14 x + 49 = 7

0 = 2 x^{2} + 8 x

(2 x + 6)^{2} = 36

900 = w (2 w - 5)

What are the solutions to the equation (2x+3)^2-108=0 ?
The solutions to the equation (2x+3)^2-108=0 are x=(6sqrt(3)-3)/2 ,x=(-6sqrt(3)-3)/2
Find the zeros of (2x+3)^2-108=0
The zeros of (2x+3)^2-108=0 are x=(6sqrt(3)-3)/2 ,x=(-6sqrt(3)-3)/2