What are the solutions to the equation 0=2x^2+8x ?

The solutions to the equation 0=2x^2+8x are x=0,x=-4

Find the zeros of 0=2x^2+8x

The zeros of 0=2x^2+8x are x=0,x=-4

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0 = 2 x^{2} + 8 x

x = 0, x = - 4

Solution steps

0 = 2 x^{2} + 8 x

Switch sides

2 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 2}, x_{2} = \frac{- 8 - 8}{2 \cdot 2}

x = \frac{- 8 + 8}{2 \cdot 2} : 0

x = \frac{- 8 - 8}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

(2 x + 6)^{2} = 36

900 = w (2 w - 5)

2 (x - 4)^{2} = 18

x^{2} + 3 x = - \frac{1}{4}

4 x^{2} = 256

What are the solutions to the equation 0=2x^2+8x ?
The solutions to the equation 0=2x^2+8x are x=0,x=-4
Find the zeros of 0=2x^2+8x
The zeros of 0=2x^2+8x are x=0,x=-4