What are the solutions to the equation s^2+16s+65=0 ?

The solutions to the equation s^2+16s+65=0 are s=-8+i,s=-8-i

Find the zeros of s^2+16s+65=0

The zeros of s^2+16s+65=0 are s=-8+i,s=-8-i

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s^{2} + 16 s + 65 = 0

s = - 8 + i, s = - 8 - i

Solution steps

s^{2} + 16 s + 65 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

Simplify

1 6^{2} - 4 \cdot 1 \cdot 65 : 2 i

s_{1, 2} = \frac{- 16 \pm 2 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 16 + 2 i}{2 \cdot 1}, s_{2} = \frac{- 16 - 2 i}{2 \cdot 1}

s = \frac{- 16 + 2 i}{2 \cdot 1} : - 8 + i

s = \frac{- 16 - 2 i}{2 \cdot 1} : - 8 - i

The solutions to the quadratic equation are:

s = - 8 + i, s = - 8 - i

(x - 4)^{2} - 28 = 8

- 4.9 t^{2} + 11.43 t + 15 = 0

(x - 2)^{2} = - 5

(x - 3)^{2} + 4 = 14

4 - x \cdot x = - 60

What are the solutions to the equation s^2+16s+65=0 ?
The solutions to the equation s^2+16s+65=0 are s=-8+i,s=-8-i
Find the zeros of s^2+16s+65=0
The zeros of s^2+16s+65=0 are s=-8+i,s=-8-i