What are the solutions to the equation (x-3)^2+4=14 ?

The solutions to the equation (x-3)^2+4=14 are x=sqrt(10)+3,x=-sqrt(10)+3

Find the zeros of (x-3)^2+4=14

The zeros of (x-3)^2+4=14 are x=sqrt(10)+3,x=-sqrt(10)+3

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(x - 3)^{2} + 4 = 14

x = 10 + 3, x = - 10 + 3

Decimal Notation

x = 6.16227 \dots, x = - 0.16227 \dots

Solution steps

(x - 3)^{2} + 4 = 14

Move

4

to the right side

(x - 3)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 10 : x = 10 + 3

Solve

x - 3 = - 10 : x = - 10 + 3

The solutions to the quadratic equation are:

x = 10 + 3, x = - 10 + 3

4 - x \cdot x = - 60

x^{2} - 20.8 x + 66.29 = 0

(x - 16)^{2} - 4 = 0

(0.0025 f^{2} - 502.5 f + 625) = 0

x^{2} - 2 x = - 6

What are the solutions to the equation (x-3)^2+4=14 ?
The solutions to the equation (x-3)^2+4=14 are x=sqrt(10)+3,x=-sqrt(10)+3
Find the zeros of (x-3)^2+4=14
The zeros of (x-3)^2+4=14 are x=sqrt(10)+3,x=-sqrt(10)+3