What are the solutions to the equation x^2-2x=-6 ?

The solutions to the equation x^2-2x=-6 are x=1+sqrt(5)i,x=1-sqrt(5)i

Find the zeros of x^2-2x=-6

The zeros of x^2-2x=-6 are x=1+sqrt(5)i,x=1-sqrt(5)i

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x^{2} - 2 x = - 6

x = 1 + 5 i, x = 1 - 5 i

Solution steps

x^{2} - 2 x = - 6

Move

6

to the left side

x^{2} - 2 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 6 : 25 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 5 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 5 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 5 i}{2 \cdot 1} : 1 + 5 i

x = \frac{- ( - 2 ) - 2 5 i}{2 \cdot 1} : 1 - 5 i

The solutions to the quadratic equation are:

x = 1 + 5 i, x = 1 - 5 i

\frac{16}{25} - x^{2} = 0

- 6 = x^{2} + 5 x

y^{2} = 5 (50)

a^{2} - a - 56 = 0

2 X^{2} - 9 X + 5 = 0

What are the solutions to the equation x^2-2x=-6 ?
The solutions to the equation x^2-2x=-6 are x=1+sqrt(5)i,x=1-sqrt(5)i
Find the zeros of x^2-2x=-6
The zeros of x^2-2x=-6 are x=1+sqrt(5)i,x=1-sqrt(5)i