What are the solutions to the equation a^2-a-56=0 ?

The solutions to the equation a^2-a-56=0 are a=8,a=-7

Find the zeros of a^2-a-56=0

The zeros of a^2-a-56=0 are a=8,a=-7

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a^{2} - a - 56 = 0

a = 8, a = - 7

Solution steps

a^{2} - a - 56 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 56) = 15

a_{1, 2} = \frac{- ( - 1 ) \pm 15}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 15}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 15}{2 \cdot 1}

a = \frac{- ( - 1 ) + 15}{2 \cdot 1} : 8

a = \frac{- ( - 1 ) - 15}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

a = 8, a = - 7

2 X^{2} - 9 X + 5 = 0

7 (x + 4) (x - 8) - \frac{224}{10} x = - \frac{224}{10} x

x, y^{2} = 9 x^{2}

5 x^{2} + 11 x = 2 x + 2

5 x^{2} = 13 x - 6

What are the solutions to the equation a^2-a-56=0 ?
The solutions to the equation a^2-a-56=0 are a=8,a=-7
Find the zeros of a^2-a-56=0
The zeros of a^2-a-56=0 are a=8,a=-7