What are the solutions to the equation 7(x+4)(x-8)-224/10 x=-224/10 x ?

The solutions to the equation 7(x+4)(x-8)-224/10 x=-224/10 x are x=-4,x=8

Find the zeros of 7(x+4)(x-8)-224/10 x=-224/10 x

The zeros of 7(x+4)(x-8)-224/10 x=-224/10 x are x=-4,x=8

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7 (x + 4) (x - 8) - \frac{224}{10} x = - \frac{224}{10} x

x = - 4, x = 8

Solution steps

7 (x + 4) (x - 8) - \frac{224}{10} x = - \frac{224}{10} x

Move

\frac{224}{10} x

to the left side

7 (x + 4) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x - 8 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 8 = 0 : x = 8

The solutions to the quadratic equation are:

x = - 4, x = 8

x, y^{2} = 9 x^{2}

5 x^{2} + 11 x = 2 x + 2

5 x^{2} = 13 x - 6

x, a x^{2} + b x + c = y

2 k^{2} + 5 k = 12

What are the solutions to the equation 7(x+4)(x-8)-224/10 x=-224/10 x ?
The solutions to the equation 7(x+4)(x-8)-224/10 x=-224/10 x are x=-4,x=8
Find the zeros of 7(x+4)(x-8)-224/10 x=-224/10 x
The zeros of 7(x+4)(x-8)-224/10 x=-224/10 x are x=-4,x=8