What are the solutions to the equation 2k^2+5k=12 ?

The solutions to the equation 2k^2+5k=12 are k= 3/2 ,k=-4

Find the zeros of 2k^2+5k=12

The zeros of 2k^2+5k=12 are k= 3/2 ,k=-4

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2 k^{2} + 5 k = 12

k = \frac{3}{2}, k = - 4

Decimal Notation

k = 1.5, k = - 4

Solution steps

2 k^{2} + 5 k = 12

Move

12

to the left side

2 k^{2} + 5 k - 12 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 12) = 11

k_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 5 + 11}{2 \cdot 2}, k_{2} = \frac{- 5 - 11}{2 \cdot 2}

k = \frac{- 5 + 11}{2 \cdot 2} : \frac{3}{2}

k = \frac{- 5 - 11}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

k = \frac{3}{2}, k = - 4

- 5 x^{2} + 9 x = - 3

(2 x - 1)^{2} - (x + 1)^{2} = 0

2 x^{2} - \frac{7}{6} x + \frac{1}{3} = 0

x^{2} - 2 x = - x^{2}

x^{2} + 4 x - 1 = 0

What are the solutions to the equation 2k^2+5k=12 ?
The solutions to the equation 2k^2+5k=12 are k= 3/2 ,k=-4
Find the zeros of 2k^2+5k=12
The zeros of 2k^2+5k=12 are k= 3/2 ,k=-4