What are the solutions to the equation x^2-2x=-x^2 ?

The solutions to the equation x^2-2x=-x^2 are x=1,x=0

Find the zeros of x^2-2x=-x^2

The zeros of x^2-2x=-x^2 are x=1,x=0

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x^{2} - 2 x = - x^{2}

x = 1, x = 0

Solution steps

x^{2} - 2 x = - x^{2}

Move

x^{2}

to the left side

2 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2}{2 \cdot 2} : 1

x = \frac{- ( - 2 ) - 2}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

x^{2} + 4 x - 1 = 0

y, x = y^{2} + 4 z^{2}

- 5 x^{2} + 10 x = 5

x^{2} + 4 x - 4 = 0

x^{2} + 4 x + 52 = 0

What are the solutions to the equation x^2-2x=-x^2 ?
The solutions to the equation x^2-2x=-x^2 are x=1,x=0
Find the zeros of x^2-2x=-x^2
The zeros of x^2-2x=-x^2 are x=1,x=0