What are the solutions to the equation -5x^2+10x=5 ?

The solutions to the equation -5x^2+10x=5 are x=1

Find the zeros of -5x^2+10x=5

The zeros of -5x^2+10x=5 are x=1

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- 5 x^{2} + 10 x = 5

x = 1

Solution steps

- 5 x^{2} + 10 x = 5

Move

5

to the left side

- 5 x^{2} + 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 5 ) ( - 5 )}{2 ( - 5 )}

1 0^{2} - 4 (- 5) (- 5) = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 ( - 5 )}

x = \frac{- 10}{2 ( - 5 )}

\frac{- 10}{2 ( - 5 )} = 1

x = 1

The solution to the quadratic equation is:

x = 1

x^{2} + 4 x - 4 = 0

x^{2} + 4 x + 52 = 0

x, x^{2} + y^{2} = 2 a x

0 = x^{2} - 5 x - 36

14 (x + 1) (x + 2) - 18 (x - 2) (x + 2) = 22 (x - 2)

What are the solutions to the equation -5x^2+10x=5 ?
The solutions to the equation -5x^2+10x=5 are x=1
Find the zeros of -5x^2+10x=5
The zeros of -5x^2+10x=5 are x=1