What are the solutions to the equation solvefor x,x^2+y^2=2ax ?

The solutions to the equation solvefor x,x^2+y^2=2ax are x=a+sqrt(-y^2+a^2),x=a-sqrt(-y^2+a^2)

Find the zeros of solvefor x,x^2+y^2=2ax

The zeros of solvefor x,x^2+y^2=2ax are x=a+sqrt(-y^2+a^2),x=a-sqrt(-y^2+a^2)

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solve for

x, x^{2} + y^{2} = 2 a x

x = a + - y^{2} + a^{2}, x = a - - y^{2} + a^{2}

Solution steps

x^{2} + y^{2} = 2 a x

Move

2 a x

to the left side

x^{2} + y^{2} - 2 a x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 a x + y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 a ) \pm ( - 2 a ) ^{2} - 4 \cdot 1 \cdot y ^{2}}{2 \cdot 1}

Simplify

(- 2 a)^{2} - 4 \cdot 1 \cdot y^{2} : 2 a^{2} - y^{2}

x_{1, 2} = \frac{- ( - 2 a ) \pm 2 a ^{2} - y ^{2}}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 a ) + 2 a ^{2} - y ^{2}}{2 \cdot 1}, x_{2} = \frac{- ( - 2 a ) - 2 a ^{2} - y ^{2}}{2 \cdot 1}

x = \frac{- ( - 2 a ) + 2 a ^{2} - y ^{2}}{2 \cdot 1} : a + - y^{2} + a^{2}

x = \frac{- ( - 2 a ) - 2 a ^{2} - y ^{2}}{2 \cdot 1} : a - - y^{2} + a^{2}

The solutions to the quadratic equation are:

x = a + - y^{2} + a^{2}, x = a - - y^{2} + a^{2}

0 = x^{2} - 5 x - 36

14 (x + 1) (x + 2) - 18 (x - 2) (x + 2) = 22 (x - 2)

x^{2} + 1.8 x - 0.225 = 0

x = (2 - x)^{2}

0 = 4 x^{2} - 260 x + 2000

What are the solutions to the equation solvefor x,x^2+y^2=2ax ?
The solutions to the equation solvefor x,x^2+y^2=2ax are x=a+sqrt(-y^2+a^2),x=a-sqrt(-y^2+a^2)
Find the zeros of solvefor x,x^2+y^2=2ax
The zeros of solvefor x,x^2+y^2=2ax are x=a+sqrt(-y^2+a^2),x=a-sqrt(-y^2+a^2)