What are the solutions to the equation x=(2-x)^2 ?

The solutions to the equation x=(2-x)^2 are x=4,x=1

Find the zeros of x=(2-x)^2

The zeros of x=(2-x)^2 are x=4,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x = (2 - x)^{2}

x = 4, x = 1

Solution steps

x = (2 - x)^{2}

Expand

(2 - x)^{2} : 4 - 4 x + x^{2}

x = 4 - 4 x + x^{2}

Switch sides

4 - 4 x + x^{2} = x

Move

x

to the left side

x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

x = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

0 = 4 x^{2} - 260 x + 2000

y, x^{3} + x^{2} y + 4 y^{2} = 6

x^{2} + 30 x + 7000 = 0

\frac{6}{7} x^{2} - x + \frac{2}{7} = 0

2 x^{2} + 4 = 3 x + 9

What are the solutions to the equation x=(2-x)^2 ?
The solutions to the equation x=(2-x)^2 are x=4,x=1
Find the zeros of x=(2-x)^2
The zeros of x=(2-x)^2 are x=4,x=1