What are the solutions to the equation 6/7 x^2-x+2/7 =0 ?

The solutions to the equation 6/7 x^2-x+2/7 =0 are x= 2/3 ,x= 1/2

Find the zeros of 6/7 x^2-x+2/7 =0

The zeros of 6/7 x^2-x+2/7 =0 are x= 2/3 ,x= 1/2

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\frac{6}{7} x^{2} - x + \frac{2}{7} = 0

x = \frac{2}{3}, x = \frac{1}{2}

Decimal Notation

x = 0.66666 \dots, x = 0.5

Solution steps

\frac{6}{7} x^{2} - x + \frac{2}{7} = 0

Multiply both sides by

7

6 x^{2} - 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 6}

x = \frac{- ( - 7 ) + 1}{2 \cdot 6} : \frac{2}{3}

x = \frac{- ( - 7 ) - 1}{2 \cdot 6} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = \frac{1}{2}

2 x^{2} + 4 = 3 x + 9

- 2 x^{2} + 4 x + 8 = 0

3 x^{2} - (- 4 x + 7) = 2 x^{2} + 5 x - 9

x, - y (x^{2} - y) - (x + 1) (x - 1) = 0

3 w^{2} - w + 5 = 6

What are the solutions to the equation 6/7 x^2-x+2/7 =0 ?
The solutions to the equation 6/7 x^2-x+2/7 =0 are x= 2/3 ,x= 1/2
Find the zeros of 6/7 x^2-x+2/7 =0
The zeros of 6/7 x^2-x+2/7 =0 are x= 2/3 ,x= 1/2