What are the solutions to the equation solvefor x,ay^2=x^2+y ?

The solutions to the equation solvefor x,ay^2=x^2+y are x=sqrt(ay^2-y),x=-sqrt(ay^2-y)

Find the zeros of solvefor x,ay^2=x^2+y

The zeros of solvefor x,ay^2=x^2+y are x=sqrt(ay^2-y),x=-sqrt(ay^2-y)

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solve for

x, a y^{2} = x^{2} + y

x = a y^{2} - y, x = - a y^{2} - y

Solution steps

a y^{2} = x^{2} + y

Switch sides

x^{2} + y = a y^{2}

Move

y

to the right side

x^{2} = a y^{2} - y

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = a y^{2} - y, x = - a y^{2} - y

- 4 x^{2} + 8000 x = 0

x^{2} + \frac{6540}{14500} x + \frac{34000}{14500} = 0

- 8 x^{2} + 1.24 x = - 0.8

x^{2} + 11 x - 27 = 5 x

2 n^{2} - 7 n + 3 = 0

What are the solutions to the equation solvefor x,ay^2=x^2+y ?
The solutions to the equation solvefor x,ay^2=x^2+y are x=sqrt(ay^2-y),x=-sqrt(ay^2-y)
Find the zeros of solvefor x,ay^2=x^2+y
The zeros of solvefor x,ay^2=x^2+y are x=sqrt(ay^2-y),x=-sqrt(ay^2-y)