What are the solutions to the equation x^2+11x-27=5x ?

The solutions to the equation x^2+11x-27=5x are x=3,x=-9

Find the zeros of x^2+11x-27=5x

The zeros of x^2+11x-27=5x are x=3,x=-9

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x^{2} + 11 x - 27 = 5 x

x = 3, x = - 9

Solution steps

x^{2} + 11 x - 27 = 5 x

Move

5 x

to the left side

x^{2} + 6 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 27) = 12

x_{1, 2} = \frac{- 6 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 12}{2 \cdot 1}, x_{2} = \frac{- 6 - 12}{2 \cdot 1}

x = \frac{- 6 + 12}{2 \cdot 1} : 3

x = \frac{- 6 - 12}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 3, x = - 9

2 n^{2} - 7 n + 3 = 0

x^{2} - 11 x + 7 = 0

x^{2} + 4 x + 4 + 8 = 0

6 y^{2} + 3 y + 24 = 0

N = 2^{3} x 5^{2} x 7^{2}

What are the solutions to the equation x^2+11x-27=5x ?
The solutions to the equation x^2+11x-27=5x are x=3,x=-9
Find the zeros of x^2+11x-27=5x
The zeros of x^2+11x-27=5x are x=3,x=-9