What are the solutions to the equation x^2+4x+4+8=0 ?

The solutions to the equation x^2+4x+4+8=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i

Find the zeros of x^2+4x+4+8=0

The zeros of x^2+4x+4+8=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i

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x^{2} + 4 x + 4 + 8 = 0

x = - 2 + 22 i, x = - 2 - 22 i

Solution steps

x^{2} + 4 x + 4 + 8 = 0

Refine

x^{2} + 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 12 : 42 i

x_{1, 2} = \frac{- 4 \pm 4 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 2 i}{2 \cdot 1}

x = \frac{- 4 + 4 2 i}{2 \cdot 1} : - 2 + 22 i

x = \frac{- 4 - 4 2 i}{2 \cdot 1} : - 2 - 22 i

The solutions to the quadratic equation are:

x = - 2 + 22 i, x = - 2 - 22 i

6 y^{2} + 3 y + 24 = 0

N = 2^{3} x 5^{2} x 7^{2}

\frac{x - 4}{4} + \frac{2 ( x - 5 )}{5} = \frac{x ^{2} - 53}{5}

x^{2} - 14 x + 39 = 0

x \cdot x = 1

What are the solutions to the equation x^2+4x+4+8=0 ?
The solutions to the equation x^2+4x+4+8=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i
Find the zeros of x^2+4x+4+8=0
The zeros of x^2+4x+4+8=0 are x=-2+2sqrt(2)i,x=-2-2sqrt(2)i