What are the solutions to the equation x(x-2)=5 ?

The solutions to the equation x(x-2)=5 are x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of x(x-2)=5

The zeros of x(x-2)=5 are x=1+sqrt(6),x=1-sqrt(6)

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x (x - 2) = 5

x = 1 + 6, x = 1 - 6

Decimal Notation

x = 3.44948 \dots, x = - 1.44948 \dots

Solution steps

x (x - 2) = 5

Expand

x (x - 2) : x^{2} - 2 x

x^{2} - 2 x = 5

Move

5

to the left side

x^{2} - 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 5) = 26

x_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 6}{2 \cdot 1} : 1 + 6

x = \frac{- ( - 2 ) - 2 6}{2 \cdot 1} : 1 - 6

The solutions to the quadratic equation are:

x = 1 + 6, x = 1 - 6

4 x - x^{2} = 4 - 2 x

0 = \frac{1}{2} x^{2} - 6 x + 21

\frac{7}{5} x + \frac{7}{5} = x^{2} - \frac{8}{5} x - \frac{13}{5}

((x - 1) x - 7 x m^{- 1} + 15) = 0

3 q^{2} - q - 12 = - 6

What are the solutions to the equation x(x-2)=5 ?
The solutions to the equation x(x-2)=5 are x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of x(x-2)=5
The zeros of x(x-2)=5 are x=1+sqrt(6),x=1-sqrt(6)