What are the solutions to the equation 10p^2+0(1-p^2)=1p^2+5(1-p^2) ?

The solutions to the equation 10p^2+0(1-p^2)=1p^2+5(1-p^2) are p=sqrt(5/14),p=-sqrt(5/14)

Find the zeros of 10p^2+0(1-p^2)=1p^2+5(1-p^2)

The zeros of 10p^2+0(1-p^2)=1p^2+5(1-p^2) are p=sqrt(5/14),p=-sqrt(5/14)

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10 p^{2} + 0 (1 - p^{2}) = 1 p^{2} + 5 (1 - p^{2})

p = \frac{5}{14}, p = - \frac{5}{14}

Decimal Notation

p = 0.59761 \dots, p = - 0.59761 \dots

Solution steps

10 p^{2} + 0 \cdot (1 - p^{2}) = 1 \cdot p^{2} + 5 (1 - p^{2})

Expand

10 p^{2} + 0 \cdot (1 - p^{2}) : 10 p^{2}

Expand

1 \cdot p^{2} + 5 (1 - p^{2}) : - 4 p^{2} + 5

10 p^{2} = - 4 p^{2} + 5

Move

4 p^{2}

to the left side

14 p^{2} = 5

Divide both sides by

14

p^{2} = \frac{5}{14}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = \frac{5}{14}, p = - \frac{5}{14}

- 16 t^{2} - 64 t + 512 = 0

r^{2} = (y - r)^{2} + (\frac{x}{2})^{2}, y

9 x^{2} = 17 x + 2

x^{2} + 10 x + 31 = 10

5 x^{2} - 20 x + 14 = 2 x + 6

What are the solutions to the equation 10p^2+0(1-p^2)=1p^2+5(1-p^2) ?
The solutions to the equation 10p^2+0(1-p^2)=1p^2+5(1-p^2) are p=sqrt(5/14),p=-sqrt(5/14)
Find the zeros of 10p^2+0(1-p^2)=1p^2+5(1-p^2)
The zeros of 10p^2+0(1-p^2)=1p^2+5(1-p^2) are p=sqrt(5/14),p=-sqrt(5/14)