What are the solutions to the equation -p^2-63p+650=62 ?

The solutions to the equation -p^2-63p+650=62 are p=-(63+7sqrt(129))/2 ,p=(7sqrt(129)-63)/2

Find the zeros of -p^2-63p+650=62

The zeros of -p^2-63p+650=62 are p=-(63+7sqrt(129))/2 ,p=(7sqrt(129)-63)/2

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- p^{2} - 63 p + 650 = 62

p = - \frac{63 + 7 129}{2}, p = \frac{7 129 - 63}{2}

Decimal Notation

p = - 71.25235 \dots, p = 8.25235 \dots

Solution steps

- p^{2} - 63 p + 650 = 62

Move

62

to the left side

- p^{2} - 63 p + 588 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 63 ) \pm ( - 63 ) ^{2} - 4 ( - 1 ) \cdot 588}{2 ( - 1 )}

(- 63)^{2} - 4 (- 1) \cdot 588 = 7129

p_{1, 2} = \frac{- ( - 63 ) \pm 7 129}{2 ( - 1 )}

Separate the solutions

p_{1} = \frac{- ( - 63 ) + 7 129}{2 ( - 1 )}, p_{2} = \frac{- ( - 63 ) - 7 129}{2 ( - 1 )}

p = \frac{- ( - 63 ) + 7 129}{2 ( - 1 )} : - \frac{63 + 7 129}{2}

p = \frac{- ( - 63 ) - 7 129}{2 ( - 1 )} : \frac{7 129 - 63}{2}

The solutions to the quadratic equation are:

p = - \frac{63 + 7 129}{2}, p = \frac{7 129 - 63}{2}

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What are the solutions to the equation -p^2-63p+650=62 ?
The solutions to the equation -p^2-63p+650=62 are p=-(63+7sqrt(129))/2 ,p=(7sqrt(129)-63)/2
Find the zeros of -p^2-63p+650=62
The zeros of -p^2-63p+650=62 are p=-(63+7sqrt(129))/2 ,p=(7sqrt(129)-63)/2