What are the solutions to the equation -x^2-x-5=0 ?

The solutions to the equation -x^2-x-5=0 are x=-1/2-i(sqrt(19))/2 ,x=-1/2+i(sqrt(19))/2

Find the zeros of -x^2-x-5=0

The zeros of -x^2-x-5=0 are x=-1/2-i(sqrt(19))/2 ,x=-1/2+i(sqrt(19))/2

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- x^{2} - x - 5 = 0

x = - \frac{1}{2} - i \frac{19}{2}, x = - \frac{1}{2} + i \frac{19}{2}

Solution steps

- x^{2} - x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) ( - 5 )}{2 ( - 1 )}

Simplify

(- 1)^{2} - 4 (- 1) (- 5) : 19 i

x_{1, 2} = \frac{- ( - 1 ) \pm 19 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 19 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 19 i}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 19 i}{2 ( - 1 )} : - \frac{1}{2} - i \frac{19}{2}

x = \frac{- ( - 1 ) - 19 i}{2 ( - 1 )} : - \frac{1}{2} + i \frac{19}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} - i \frac{19}{2}, x = - \frac{1}{2} + i \frac{19}{2}

x, x^{2} + 10 x + 12 = 36

2 x^{2} + 27 x - 14 = 0

- 6 x = x^{2} + 8

x^{2} + 2 x = - 17

8^{2} + 7^{2} = c^{2}

What are the solutions to the equation -x^2-x-5=0 ?
The solutions to the equation -x^2-x-5=0 are x=-1/2-i(sqrt(19))/2 ,x=-1/2+i(sqrt(19))/2
Find the zeros of -x^2-x-5=0
The zeros of -x^2-x-5=0 are x=-1/2-i(sqrt(19))/2 ,x=-1/2+i(sqrt(19))/2