What are the solutions to the equation x^2-12x+117=0 ?

The solutions to the equation x^2-12x+117=0 are x=6+9i,x=6-9i

Find the zeros of x^2-12x+117=0

The zeros of x^2-12x+117=0 are x=6+9i,x=6-9i

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x^{2} - 12 x + 117 = 0

x = 6 + 9 i, x = 6 - 9 i

Solution steps

x^{2} - 12 x + 117 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 117}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 117 : 18 i

x_{1, 2} = \frac{- ( - 12 ) \pm 18 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 18 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 18 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 18 i}{2 \cdot 1} : 6 + 9 i

x = \frac{- ( - 12 ) - 18 i}{2 \cdot 1} : 6 - 9 i

The solutions to the quadratic equation are:

x = 6 + 9 i, x = 6 - 9 i

n C^{2} = 45

12 t^{2} + 6 t - 6 = 0

(x - 1296) (x + 1296) = 0

- 2 x^{2} - x = 9

x, (3 x - y)^{2} + (x - 5)^{2} = 0

What are the solutions to the equation x^2-12x+117=0 ?
The solutions to the equation x^2-12x+117=0 are x=6+9i,x=6-9i
Find the zeros of x^2-12x+117=0
The zeros of x^2-12x+117=0 are x=6+9i,x=6-9i