What are the solutions to the equation 12t^2+6t-6=0 ?

The solutions to the equation 12t^2+6t-6=0 are t= 1/2 ,t=-1

Find the zeros of 12t^2+6t-6=0

The zeros of 12t^2+6t-6=0 are t= 1/2 ,t=-1

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12 t^{2} + 6 t - 6 = 0

t = \frac{1}{2}, t = - 1

Decimal Notation

t = 0.5, t = - 1

Solution steps

12 t^{2} + 6 t - 6 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

6^{2} - 4 \cdot 12 (- 6) = 18

t_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 12}

Separate the solutions

t_{1} = \frac{- 6 + 18}{2 \cdot 12}, t_{2} = \frac{- 6 - 18}{2 \cdot 12}

t = \frac{- 6 + 18}{2 \cdot 12} : \frac{1}{2}

t = \frac{- 6 - 18}{2 \cdot 12} : - 1

The solutions to the quadratic equation are:

t = \frac{1}{2}, t = - 1

(x - 1296) (x + 1296) = 0

- 2 x^{2} - x = 9

x, (3 x - y)^{2} + (x - 5)^{2} = 0

4 x - x^{2} = 2 x

x, x^{2} + m x + 9 = 0

What are the solutions to the equation 12t^2+6t-6=0 ?
The solutions to the equation 12t^2+6t-6=0 are t= 1/2 ,t=-1
Find the zeros of 12t^2+6t-6=0
The zeros of 12t^2+6t-6=0 are t= 1/2 ,t=-1