What are the solutions to the equation 4x-x^2=2x ?

The solutions to the equation 4x-x^2=2x are x=0,x=2

Find the zeros of 4x-x^2=2x

The zeros of 4x-x^2=2x are x=0,x=2

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4 x - x^{2} = 2 x

x = 0, x = 2

Solution steps

4 x - x^{2} = 2 x

Move

2 x

to the left side

- x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2}{2 ( - 1 )}

x = \frac{- 2 + 2}{2 ( - 1 )} : 0

x = \frac{- 2 - 2}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = 0, x = 2

x, x^{2} + m x + 9 = 0

0 = x^{2} - 8 x + 19

- \frac{1}{3} x^{2} - 10 x + 112 = \frac{1}{4} x^{2} + 5 x + 1

x, x^{2} + y^{2} + z^{2} = 2 y

(4 - 4 x + x^{2}) (6 \cdot 1 0^{- 6}) = x^{2} (15 \cdot 1 0^{- 6})

What are the solutions to the equation 4x-x^2=2x ?
The solutions to the equation 4x-x^2=2x are x=0,x=2
Find the zeros of 4x-x^2=2x
The zeros of 4x-x^2=2x are x=0,x=2