What are the solutions to the equation 17-4x=16x^2+24x-8 ?

The solutions to the equation 17-4x=16x^2+24x-8 are x=(-7+sqrt(149))/8 ,x=-(7+sqrt(149))/8

Find the zeros of 17-4x=16x^2+24x-8

The zeros of 17-4x=16x^2+24x-8 are x=(-7+sqrt(149))/8 ,x=-(7+sqrt(149))/8

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17 - 4 x = 16 x^{2} + 24 x - 8

x = \frac{- 7 + 149}{8}, x = - \frac{7 + 149}{8}

Decimal Notation

x = 0.65081 \dots, x = - 2.40081 \dots

Solution steps

17 - 4 x = 16 x^{2} + 24 x - 8

Switch sides

16 x^{2} + 24 x - 8 = 17 - 4 x

Move

4 x

to the left side

16 x^{2} + 28 x - 8 = 17

Move

17

to the left side

16 x^{2} + 28 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 16 ( - 25 )}{2 \cdot 16}

2 8^{2} - 4 \cdot 16 (- 25) = 4149

x_{1, 2} = \frac{- 28 \pm 4 149}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 28 + 4 149}{2 \cdot 16}, x_{2} = \frac{- 28 - 4 149}{2 \cdot 16}

x = \frac{- 28 + 4 149}{2 \cdot 16} : \frac{- 7 + 149}{8}

x = \frac{- 28 - 4 149}{2 \cdot 16} : - \frac{7 + 149}{8}

The solutions to the quadratic equation are:

x = \frac{- 7 + 149}{8}, x = - \frac{7 + 149}{8}

0 = 537.5 - 125 (x - 35) + 7.2 (x - 35)^{2}

x, 0.5 + 0.5 y = (1 + y) x - y x^{2}

x^{2} + 10 x = 18

x^{2} - 18 x + 130 = 0

(x + 4)^{2} - 3 (x + 4) - 3 = 0

What are the solutions to the equation 17-4x=16x^2+24x-8 ?
The solutions to the equation 17-4x=16x^2+24x-8 are x=(-7+sqrt(149))/8 ,x=-(7+sqrt(149))/8
Find the zeros of 17-4x=16x^2+24x-8
The zeros of 17-4x=16x^2+24x-8 are x=(-7+sqrt(149))/8 ,x=-(7+sqrt(149))/8