What are the solutions to the equation x^2+10x=18 ?

The solutions to the equation x^2+10x=18 are x=-5+sqrt(43),x=-5-sqrt(43)

Find the zeros of x^2+10x=18

The zeros of x^2+10x=18 are x=-5+sqrt(43),x=-5-sqrt(43)

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x^{2} + 10 x = 18

x = - 5 + 43, x = - 5 - 43

Decimal Notation

x = 1.55743 \dots, x = - 11.55743 \dots

Solution steps

x^{2} + 10 x = 18

Move

18

to the left side

x^{2} + 10 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 18) = 243

x_{1, 2} = \frac{- 10 \pm 2 43}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 43}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 43}{2 \cdot 1}

x = \frac{- 10 + 2 43}{2 \cdot 1} : - 5 + 43

x = \frac{- 10 - 2 43}{2 \cdot 1} : - 5 - 43

The solutions to the quadratic equation are:

x = - 5 + 43, x = - 5 - 43

x^{2} - 18 x + 130 = 0

(x + 4)^{2} - 3 (x + 4) - 3 = 0

x, w x^{2} + w = 0

x^{2} + 650 = 63 x

x^{2} - 11 x - 126 = 0

What are the solutions to the equation x^2+10x=18 ?
The solutions to the equation x^2+10x=18 are x=-5+sqrt(43),x=-5-sqrt(43)
Find the zeros of x^2+10x=18
The zeros of x^2+10x=18 are x=-5+sqrt(43),x=-5-sqrt(43)